Table of Contents
How do you find the maximum height of an arrow?
The height in feet of the arrow t seconds after it was shot into the air is given by the function h t = −16t2 + 160t. It takes 5 seconds for the arrow to reach its maximum height. The maximum height of the arrow is 400 feet.
What is the initial velocity of an arrow?
Initial velocity is 250 m/s straight up. Gravity is acting on it the entire time with a magnitude of 9.8ms2 straight down. Need to find time for it to come back to the ground. So at the end of the flight of the arrow, s=0.
How long does it take for the arrow to reach the ground?
approximately 8.05 seconds
The arrow will hit the ground is approximately 8.05 seconds.
How do you find out how high something went?
How to find the maximum height of a projectile?
- if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest.
- if α = 45°, then the equation may be written as:
- if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that’s the case of horizontal projectile motion.
How do you figure out how high something goes straight up?
h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
How do you find initial velocity?
How do you find initial velocity?
- Work out which of the displacement (S), final velocity (V), acceleration (A) and time (T) you have to solve for initial velocity (U).
- If you have V, A and T, use U = V – AT.
- If you have S, V and T, use U = 2(S/T) – V.
- If you have S, V and A, use U = SQRT(V2 – 2AS).
What is the motion of an arrow?
The two forces combined will cause the arrow to move in the curved path shown in the Figure below. This type of motion is called projectile motion. It occurs whenever an object curves down toward the ground because it has both a horizontal force and the downward force of gravity acting on it.
How far from the base of the cliff will the arrow land?
The arrow will take 3 seconds to hit the ground. The arrow will land 127 meters from the cliff.
What is the formula for finding maximum height?
h = v 0 y 2 2 g . h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
How do you find the maximum height of a ball thrown in the air?
We know the value of g in SI is 9.8 m/second square. So just for example, if a ball is thrown vertically upwards with 98 m/s velocity, then to reach the maximum height it will take = 98/9.8 =10 seconds.