What results would you expect if the experiment started with a glucose and IKI solution inside the bag and only starch and water outside Why?

What results would you expect if the experiment started with a glucose and IKI solution inside the bag and only starch and water outside Why?

What results would you expect if the experiment started with a glucose and IKI solution inside the bag and only starch and water outside? Based on the size of the molecules, the glucose and IKI would move out of the bag and the water would go in. The large starch molecules would be left in the beaker.

What conclusions can you make about the relative size of glucose sucrose NaCl and water molecules?

What conclusion can one make about the relative sizes of glucose, starch, NaCl, and water? The conclusion one can make about the relative sizes of glucose, starch, NaCl, and water is that there are certain molecules that membranes are permeable to.

What would happen to the mass of each bag in the experiment if they were placed in a 0.4 M sucrose solution instead of distilled water?

Predict what would happens to the mass of each bag in this experiment if all the bags were placed in a 0.4M sucrose instead of distilled water. They would diffuse until they reached equilibrium, Since the bags were placed in distilled water, the water diffused into the bag making the mass increase.

What can you conclude about the diffusion of iodine glucose and starch across the selectively permeable dialysis tubing membrane?

What can you conclude about the diffusion of iodine,glucose, and starch across the selectively permeable dialysis tubing membrane? Diffusion occurred based on molecular size. Iodine and glucose are much smaller molecules than starch; therefore, they were able to diffuse.

What does your data tell you about the sizes of the molecules relative to the pore size of the dialysis tubing?

Lab Activity A: What does your data tell you about the sizes of the molecules relative to the pore size of the dialysis tubing? The data tells me that a polysaccharide like starch is too big to pass through the dialysis tubing. The pore size is too small while the polysaccharide is too large.

What will eventually happen to the concentration beaker 2?

What will eventually happen to the concentrations in beaker 2? 100% Water will reach equilibriu in & 0% Starch be 15% starch ..

How are dialysis tubing membranes different from living animal cell membranes?

The dialysis tubing only cares about size. A biological membrane is composed of phospholipid bilayer, while the dialysis tubing is composed of cellulose. The cell membrane interacts with the outside environment with the use of its proteins, and interacts with other cells as well, wheres dialysis tubing can’t.

Which color mystery solution has the highest concentration of sucrose How do you know this?

blue mystery solution
Which color mystery solution had the highest concentration of sucrose? How do you know this? The blue mystery solution had the highest concentration of sucrose, since the core weighed the least at the end of the 30 minutes.

Why did the different lab groups have bags with different weights?

Bags 1,2,3 and 4 were placed in separate beakers of DI water. Bags 2-4 all gained weight because the sucrose solution could not leave the bag, yet it was hypertonic to its environment. This concentration gradient caused water to diffuse into the dialysis tubes making the tubes gain weight.

How does change in mass change with sucrose concentration molarity?

As they are placed in a more dilute solution, their mass increases. As the molarity of sucrose increases, the water diffuses out of the potatoes and their mass decreases.

Did starch diffuse through the membrane?

Starch does not pass through the synthetic selectively permeable membrane because starch molecules are too large to fit through the pores of the dialysis tubing. In contrast, glucose, iodine, and water molecules are small enough to pass through the membrane. Diffusion results from the random motion of molecules.

How does membrane potential affect the rate of pore formation?

First, we examined Mag-generated membrane permeation of the water-soluble fluorescent probe calcein in single DOPG/DOPC-GUVs in the presence of membrane potential. The results indicate that the rate constant ( kp) of Mag-induced pore formation increased with increasing negative membrane potentials.

How does membrane potential affect calcein leakage from GUVs?

Magainin 2 (Mag) caused leakage of calcein from GUVs under membrane potential, φm. Rate constant of Mag-induced pore formation ( kp) increased as ∣ φm ∣ increased. Binding constant of CF-Mag to GUV membrane increased with an increase in ∣ φm ∣. Under φm, Mag locates in outer leaflet of GUV until just before pore formation.

What causes rate constant of Mag-induced pore formation ( KP )?

Rate constant of Mag-induced pore formation ( kp) increased as ∣ φm ∣ increased. Binding constant of CF-Mag to GUV membrane increased with an increase in ∣ φm ∣. Under φm, Mag locates in outer leaflet of GUV until just before pore formation. Increase in Mag surface concentration is one of main causes of the increase in kp.

How are membrane potentials generated in Gramicidin A?

Various membrane potentials in GUVs containing gramicidin A were generated as a result of K + concentration gradients. First, we examined Mag-generated membrane permeation of the water-soluble fluorescent probe calcein in single DOPG/DOPC-GUVs in the presence of membrane potential.