Table of Contents
How to calculate the frequency of a dominant allele?
Answer: The frequency of the dominant (normal) allele in the population (p) is simply 1 – 0.02 = 0.98 (or 98%). The percentage of heterozygous individuals (carriers) in the population. Answer: Since 2pq equals the frequency of heterozygotes or carriers, then the equation will be as follows: 2pq = (2)(.
How to find frequency of dominant phenotype?
Use the Hardy-Weinberg equilibrium.
- Alleles: p+q=1.
- p=frequency of the dominant allele.
- p2=frequency of homozygous dominant genotype.
- In your scenario, the dominant phenotype has a frequency of 0.19 .
- This is misleading, since both the p2 and 2pq terms represent the dominant phenotype.
- If q2=0.81 , we can determine q .
How do you solve allele frequencies?
Allele Frequency
- Allele frequency is most commonly calculated using the Hardy-Weinberg equation, which describes the relationship between two alleles within a population.
- To find the number of alleles in a given population, you must look at all the phenotypes present.
- 1 = p2 + 2pq + q2
What does P represent in the Hardy-Weinberg equation?
The Hardy-Weinberg Equation The terms of this equation are defined as follows: p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population.
How do you calculate p and q allele frequencies?
The Hardy-Weinberg equation used to determine genotype frequencies is: p2 + 2pq + q2 = 1. Where ‘p2’ represents the frequency of the homozygous dominant genotype (AA), ‘2pq’ the frequency of the heterozygous genotype (Aa) and ‘q2’ the frequency of the homozygous recessive genotype (aa).
What is 2pq?
In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
Which is the frequency of the recessive allele in the population?
To determine q, which is the frequency of the recessive allele in the population, simply take the square root of q 2 which works out to be 0.632 (i.e. 0.632 x 0.632 = 0.4). So, q = 0.63. Since p + q = 1, then p must be 1 – 0.63 = 0.37. Now then, to answer our questions.
How to calculate the frequency of homozygous dominant individuals?
The frequency of homozygous dominant individuals. Answers: The first thing you’ll need to do is obtain p and q. So, since white is recessive (i.e. bb), and 40% of the butterflies are white, then bb = q 2 = 0.4.
How are homozygous red blood cells affected by malaria?
Normal homozygous individials (SS) have normal blood cells that are easily infected with the malarial parasite. Thus, many of these individuals become very ill from the parasite and many die. Individuals homozygous for the sickle-cell trait (ss) have red blood cells that readily collapse when deoxygenated.
Why are the frequencies of the two phenotypes different?
The frequencies of the two possible phenotypes if “A” is completely dominant over “a.” Answers: Because “A” is totally dominate over “a”, the dominant phenotype will show if either the homozygous “AA” or heterozygous “Aa” genotypes occur.