How many address lines are required to access 2 MB How many of these lines are connected to the address inputs of all chips?

How many address lines are required to access 2 MB How many of these lines are connected to the address inputs of all chips?

How many address lines are required to access 2 MB How many of these lines are connected to the address inputs of all chips? Answer is 21. Now 1048576 Byte = 2^20 Byte means for 1MB we need 20 address lines. So 2MB = 2*2^20=4^20=2^21 ; means for 2MB we need 21 address lines.

How many address lines are required to addressing 1MB memory?

“20” address lines or address bus are required to span “1MB” memory space.

How many address and data lines in bus are required for 2gb memory?

The memory locations for this memory are numbered 0 through 2 22 -1. Thus, the memory bus of this system requires at least 22 address lines.

How many bits are required to address 2gb memory What is the address range of this memory?

210 = 1024, so you need 10 bits to address every byte in a kilobyte. Likewise, you need 20 bits to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte. 232 = 4294967296, which is the number of bytes in 4 gigabytes, so you need a 32 bit address for 4 GB of memory.

How many address lines are needed for the memory unit 2m * 16?

Since there are 16M words, the number of address lines will be 24, since 224 = 16M. Also since the word size is 32 bits, the number of data lines will also be 32.

How many address lines are required?

Address lines needed to address each memory location – Example – Networking. It means that a memory of 2048 words, where each word is 4 bits. So to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, so 11 address lines.

How many address lines would be required to address 128 MB directly?

128 bits = 16 bytes, so you need 4 address lines less (28 instead of 32).

How many address bits are required for a 1024 * 8 memory?

How many address bits are required for a 1024 * 8 memory? Or 1024*8 gives 8192, or 2^13. so 13 bits. If it ain’t a 1024 bits multiplied by 8 bits, or there are 1024 arrays of each size of 8 bit, then 1024 arrays, so 10 bits of addresses will do it.

What is the relationship between size of a memory and number of address lines required for it?

2 Answers. To express in very easy terms, without any bus-multiplexing, the number of bits required to address a memory is the number of lines (address or data) required to access that memory. Quoting from the Wikipedia article, a system with a 32-bit address bus can address 232 (4,294,967,296) memory locations.

How many data lines and address lines are required for 1gb and 128 bits data transfer of RAM?

It depends on the processor, and its RAM interface. Some processors will transmit data to and from RAM 128 bits at a time, for example, and individual bytes are sorted out within the processor. 128 bits = 16 bytes, so you need 4 address lines less (28 instead of 32).