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How many moles of CL are in AlCl3?

How many moles of CL are in AlCl3?

3 mol
1 mol aluminium chloride AlCl3 delivers 3 mol of Cl− ions.

How many moles of AlCl3 are formed?

Solving these equations, we see that, beginning with 6.0 grams of aluminum, 0.22 moles of AlCl3 can be formed, and that, beginning with 3.8 grams of chlorine, 0.036 moles of AlCl3 can be formed.

How many atoms of chlorine are there?

But the question asked is “how many atoms are present?” Because each molecule of Chlorine contains two atoms, the answer is 2 x 1.607 x 1024 atoms are present = 3.22 x 1024 atoms.

How many chloride ions are there in 4.50 moles of AlCl3?

It is known that 1mol=6.02×1023ions 1 m o l = 6.02 × 10 23 i o n s . Hence, 8.13×1024 8.13 × 10 24 chloride ions are there in 4.50 moles of aluminum chloride.

How many total atoms are in aluminum hydroxide?

It has a total of three elements and seven atoms. Another use that aluminum hydroxide has is it treats the symptoms of too much stomach acid. Some examples of what it treats are: upset stomach, heartburn, and acid indigestion.

What is the mole ratio of aluminum to aluminum chloride?

The balanced chemical equation represents the mole ratio in which the chemicals combine, and in this case illustrates that 2molAl produces 2molAlCl3 , hence these 2 chemicals are in a 1:1 ratio.

How many moles of AlCl3 will be produced if 2.50 moles of Al react?

How many grams of AlCl3 will be produced if 2.50 moles of Al react? The coefficients before Al and AlCl3 are equal, so from 2.50 moles of Al 2.50 moles of AlCl3 are obtained. m(AlCl3)=2.50*133.5=333.75(g).

How many chlorine atoms are there in 2 moles of chlorine?

2 Answers. 3.6⋅1024 Chlorine atoms.

How many cl2 molecules are there in 10 moles of chlorine gas?

If you have a mole of cl2, then you have 6.02 * 10^23 molecules of cl2. If you want to calculate for atoms however, you can see that each molecule has two atoms of cl. Therefore you have 2* 6.02 * 10^23 chlorine atoms.

How many moles of chloride ions are in .2580 g of aluminum chloride?

So, 5.805×10−3mol 5.805 × 10 − 3 m o l of chloride ions are present in 0.2580 g of aluminum chloride.