Table of Contents
What is the balanced equation of Cu O2?
Cu is a reducing agent, O 2 is an oxidizing agent….Search by reactants (Cu, O 2) and by products (CuO)
1 | O2 + Cu → CuO |
---|---|
3 | H2O + O2 + CO2 + Cu → CuO + CuCO3*Cu(OH)2 |
Can CU react with O2?
For example, copper and oxygen react together to make copper oxide. Copper and oxygen are the reactants because they are on the left of the arrow. Copper oxide is the product because it is on the right of the arrow.
What is CU and O2?
Copper oxide is a compound from the two elements copper and oxygen. Copper(I) oxide (cuprous oxide, Cu2O) Copper(II) oxide (cupric oxide, CuO)
What type of reaction is Cu O2 2cuo?
Answer: The aforementioned reaction is an oxidation reaction. In this reaction, the oxidation of copper having chemical symbol Cu, is taking place.
Is Cu o2 endothermic?
Also we can see that when copper combines with oxygen to form copper oxide then an amount of energy is released. This is known as enthalpy of the reaction. Since it is written on the product side, it is positive energy which means that during the reaction the energy is released. Therefore it is an exothermic reaction.
What type of reaction is Cu o2 2cuo?
What type of reaction is CO2 → C O2?
It is a combination reaction as carbon combines with oxygen to form carbon dioxide. It is a combustion reaction as carbon is burnt in the presence of oxygen.
How do you write copper in an equation?
Copper + oxygen→ copper (II) oxide. Hint: Copper oxide or cupric oxide is the inorganic compound with the formula $CuO$. It is one of the two stable oxides of copper. When the cupric oxide is heated with metallic copper, it is further converted into cuprous oxide.
Is CU O2 a redox reaction?
The word ‘redox’ is derived from two words –reduction and oxidation. Oxidation is a process of addition of oxygen or removal of hydrogen. Copper combines with oxygen to form copper oxide.
Is 2mg O2 → 2mgo balanced?
Magnesium reacts with oxygen to produce magnesium oxide. reactants: 2 × Mg, 2 × O products: 2 × Mg, 2 × O This chemical equation is now balanced.