What is the difference between NP and NP complete?

What is the difference between NP and NP complete?

A problem X is NP-Complete if there is an NP problem Y, such that Y is reducible to X in polynomial time. NP-Complete problems are as hard as NP problems….Difference between NP-Hard and NP-Complete:

NP-hard	NP-Complete
Do not have to be a Decision problem.	It is exclusively a Decision problem.

Is NP equal to NP-complete?

What is the point of classifying the two if they are the same? In other words, if we have an NP problem then through (2) this problem can transform into an NP-complete problem. Therefore, the NP problem is now NP-complete, and NP = NP-complete. Both classes are equivalent.

What is NP but not NP-complete?

This means that any complete problem for a class (e.g. PSPACE) which contains NP is also NP-hard. In order to get a problem which is NP-hard but not NP-complete, it suffices to find a computational class which (a) has complete problems, (b) provably contains NP, and (c) is provably different from NP.

What is NP completeness is P NP explain?

P is a set of problems that can be solved by a deterministic Turing machine in Polynomial time. NP is set of decision problems that can be solved by a Non-deterministic Turing Machine in Polynomial time. Therefore, the NP-Complete set is also a subset of the NP-Hard set.

Is chess a NP?

For two-player games, one encounters a similar phenomenon at a higher level of complexity. For this reason games like chess cannot themselves be NP-complete, as they only have a finite (albeit unthinkably large) number of possible positions.

Is Sudoku NP-complete?

Introduction. The generalised Sudoku problem is an NP-complete problem which, effectively, requests a Latin square that satisfies some additional constraints. In addition to the standard requirement that each row and column of the Latin square contains each symbol precisely once, Sudoku also demands block constraints.

Is P NP-complete?

NP-hard problems are those at least as hard as NP problems; i.e., all NP problems can be reduced (in polynomial time) to them. If any NP-complete problem is in P, then it would follow that P = NP. However, many important problems have been shown to be NP-complete, and no fast algorithm for any of them is known.

Why is NP-complete important?

NP-complete languages are significant because all NP-complete languages are thought of having similar hardness, in that process solving one implies that others are solved as well. If some NP-complete languages are proven to be in P, then all of NPs are proven to be in P.

Is Othello NP-complete?

Iwata and T. Kasai, The Othello game on an n*n board is PSPACE-complete, Theor.

Why is TSP not NP-complete?

Why is TSP not NP-complete? The simple answer is that it’s NP-hard, but it’s not in NP. Since it’s not in NP, it can’t be NP-complete. In TSP you’re looking for the shortest loop that goes through every city in a given set of cities.