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What is the largest number divisible by 11?
What is the Smallest and the Largest 4-Digit Number Divisible by 11? 1001 is the smallest and 9999 is the largest 4 digit number divisible by 11. In 1001, the difference between the sum of the digits at the odd and even places starting from the left to right is (1+0) – (0+1), which is 0.
Which of the following number is divisible by both 8 and 11?
Thus the only possible values of sum are 5, 10 and 13. In the given options only 10 is there. So it is the correct choice. This discussion on The number A39K2 is completely divisible by both 8 and 11.
Which is the number divisible by 11?
A number is divisible by 11, if the difference of sum of its digits in odd places from the right side and the sum of its digits in even places from the right side is divisible by 11. Since difference is 11 which is divisible by 11, therefore 5918 is divisible by 11.
What numbers can be divisible by 8?
A number is divisible by 8 if its last three digits are divisible by 8. For example, 880 and 905,256 are divisible by 8 but 74,513 is not divisible by 8. To check divisibility by 8, divide the last three digits of the number by 8.
What is the largest two digit number divisible by 11?
The two-digit numbers which are divisible by 11 are 11, 22, 33, 44, 55, 66, 77, 88, 99. Hence, there are 9 two-digit number which are divisible by 11.
Which of the following numbers is divisible by 11 Brainly?
Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.
Which of the greatest 4 digit number is exactly divisible by 8?
9960 is the greatest 4-digit number divisible by 8, 12 and 14.
How do you test for divisibility by 11?
Here an easy way to test for divisibility by 11. Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11.
What is the remainder when is divided by 11?
The remainder is 2 because the quotient is 0 (11 goes into 2 zero times).
Which of the given numbers is not divisible by 11?
Then, we know only 0 and multiples of 11 as 11, 22, 33 and so on will be divisible by 11. Now, we can clearly see only the number 888888 gives the number as 0 which is divisible by 11 and all other numbers are not divisible by 11. Therefore the total number of numbers which are not divisible by 11 are 6.
Which statement support the divisibility rule for number 11?
The statement is as follows: If the difference between the sum of the odd-numbered digits and the sum of the even-numbered digits, counted from right to left, is divisible by 11, then the number is divisible by 11.
How do you show that something is divisible by 8?
Divisibility by 8
- Rule for Divisibility by 8. A number with at least 3 digits is divisible by 8 if its last three digits form a number divisible by 8.
- Examples. A.)
- Proof. For any integer x written as anan-1an-2…a2a1a0, we will show that x is divisible by 8 if a2a1a0 is divisible by 8.