Table of Contents

- 1 How do you find the sum of the first 25 terms?
- 2 What is the sum of 25 terms of an AP?
- 3 What is the sum of first 25?
- 4 What is the sum of 25 terms of an AP whose nth term is 7?
- 5 How do you find the sum of terms in AP?
- 6 How do you find total terms in AP?
- 7 How many terms of the AP 9 17/25 must be taken to give a sum of 636?

## How do you find the sum of the first 25 terms?

Since the n th term of an arithmetic sequence is given by the following formula: an=a1+d(n−1) , where d is the common difference. So the sum of the first 25 terms of your series is 3775.

## What is the sum of 25 terms of an AP?

The sum of 25 terms of an A.P., whose all the terms are natural numbers, lies between 1900 and 2000 and its 9^(th) term is 55.

**What is the formula of sum of first n terms of an AP?**

The sum of n terms of AP is the sum(addition) of first n terms of the arithmetic sequence. It is equal to n divided by 2 times the sum of twice the first term – ‘a’ and the product of the difference between second and first term-‘d’ also known as common difference, and (n-1), where n is numbers of terms to be added.

### What is the sum of first 25?

325

Hence, the sum of the first 25 natural numbers is 325, which is option (a).

### What is the sum of 25 terms of an AP whose nth term is 7?

Find the sum of first 25 terms of an A.P whose nth term is given by an = 7 – 3n. Hence, the sum of the first 25 terms of given A.P. is -800.

**What is the sum of the first 25 natural odd numbers?**

625

Therefore, the sum of first 25 odd numbers is 625.

## How do you find the sum of terms in AP?

The formula to find the sum of n terms in AP is Sn = n/2 (2a+(n−1)d), in which a = first term, n = number of terms, and d = common difference between consecutive terms.

## How do you find total terms in AP?

To find the number of terms in an arithmetic sequence, divide the common difference into the difference between the last and first terms, and then add 1.

**What is the formula of sum of AP?**

Formula Lists

General Form of AP | a, a + d, a + 2d, a + 3d, . . . |
---|---|

The nth term of AP | an = a + (n – 1) × d |

Sum of n terms in AP | S = n/2[2a + (n − 1) × d] |

Sum of all terms in a finite AP with the last term as ‘l’ | n/2(a + l) |

### How many terms of the AP 9 17/25 must be taken to give a sum of 636?

Number of terms of the AP [ 9 , 17 , 25 ] which are required to make the sum of 636 is 12.